Multiplication of Polynomials
The multiplication operation on polynomials follows the general properties like commutative property, associative property, distributive property, etc. Applying these properties using the rules of exponents we can solve the multiplication of polynomials. To multiply to polynomials, we just multiply every term of one polynomial with every term of the other polynomial and then add all the results. Here is an example to multiply polynomials.
Example: (2x + 3y)(4x – 5y)
= 2x(4x – 5y) + 3y(4x – 5y)
= 8x2 – 10xy + 12xy – 15y2
⇒ 8x2 + 2xy – 15y2
Example: Solve (6x−3y)×(2x+5y)
Solution:
⇒ 6x ×(2x+5y)–3y × (2x+5y) ———- Using distributive law of multiplication
⇒ (12x2+30xy) – (6yx+15y2) ———- Using distributive law of multiplication
⇒12x2+30xy–6xy–15y2 —————– as xy = yx
Thus, (6x−3y)×(2x+5y)=12x2+24xy−15y2
Division of Polynomials
The division of polynomials is an arithmetic operation where we divide a given polynomial by another polynomial which is generally of a lesser degree in comparison to the degree of the dividend. There are two methods to divide polynomials.
- Long division of polynomials
- Synthetic division
Long Division of Polynomials
Long division of polynomials is the process of dividing one polynomial with another. Division can be done among the different types of polynomials i.e. between two monomials, a polynomial and a monomial, or between two polynomials. A polynomial is n algebraic expression with variables, terms, and coefficients with the degree of the expressions.
In algebra, the division of algebraic expressions can be done in three ways:
- Division of a monomial by another monomial.
- Division of a polynomial by a monomial.
- Division of a polynomial by a binomial.
- Division of a polynomial by another polynomial.
Steps For Long Division of Polynomials
The following are the steps for the long division of polynomials:
- Step 1. Arrange the terms in the decreasing order of their indices (if required). Write the missing terms with zero as their coefficient.
- Step 2. For the first term of the quotient, divide the first term of the dividend by the first term of the divisor.
- Step 3. Multiply this term of the quotient by the divisor to get the product.
- Step 4. Subtract this product from the dividend, and bring down the next term (if any). The difference and the brought down term will form the new dividend.
- Step 5. Follow this process until you get a remainder, which can be zero or of a lower index than the divisor.
Long Division of Polynomial by Missing Terms
While performing long division of polynomials, there can be a missing term in the expression, for example, 6x4 + 3x – 9x2 + 6, x3 is missing. In this case, we either leave a gap while dividing or we write the coefficient as zero. Let’s understand how to do the long division of polynomials with the same example. We need to divide the polynomial a(x) = 6x4 + 3x – 9x2 + 6 by the quadratic polynomial b(x) = x2 – 2
Arrange the polynomial in the descending order of the power of the variable.
a(x) = 6x4 – 9x2 + 3x + 6
b(x) = x2 – 2
Divide a(x) by b(x) in the same way as we divide numbers.
Add the missing indices with zero (0) as the coefficient.
Divide 6x4 by x2 to get the first term of the quotient. We get 6x2.
Multiply the divisor by 6x2.
Divide 3x2 by x2 to get the next term of the quotient.
As the power of the next dividend is less than the divisor, we get our required remainder. Please remember that as the remainder we got is a non-zero term, we can say that x2 – 2 is not a factor of 6x4 – 9x2 + 3x + 6. Therefore, the quotient is 6x2 + 3 and the remainder is 3x.
Long Division of Polynomials by Monomials
While dividing polynomials by monomials, write the common factor between the numerator and the denominator of the polynomial and divide each term separately. Once the result is obtained, add all the terms together to form an expression.
For example:
Divide the following polynomial: (2x2 + 4x + 8xy) ÷ 2x.
Both the numerator and denominator have a common factor of 2x. Thus, the expression can be written as 2x(x + 2 + 4y) / 2x.
Canceling out the common term 2x, we get x + 4y + 2 as the answer.
Long Division of Polynomials by Other Monomial
Long division of polynomials by another monomial is done in a similar manner as done for polynomials by monomials. The factors of the monomial of both the numerator and denominator are listed out and the long division takes place.
For example, divide 62x3 by 2x. The factors of 62x3 = 2 × 31 × x × x × x and 2x = 2 × x. The common factors for both are 2x. Hence, 62x3/2x = 31x2.
Long Division of Polynomials by Binomials
Long division of polynomials by binomials is done when there are no common factors between the numerator and the denominator, or if you can’t find the factors.
Let us go through the algorithm of dividing polynomials by binomials using an example:
Divide: (6x2 – 4x – 24) ÷ (x – 3). Here, (6x2 – 4x – 24) is the dividend, and (x – 3) is the divisor which is a binomial. Observe the division shown below, followed by the steps.
- Step 1. Divide the first term of the dividend (6x2) by the first term of the divisor (x), and put that as the first term in the quotient (6x).
- Step 2. Multiply the divisor by that answer, place the product (6x2 – 18x) below the dividend.
- Step 3. Subtract to create a new polynomial (14x – 24).
- Step 4. Repeat the same process with the new polynomial obtained after subtraction.
So, when we are dividing a polynomial (6x2 – 4x – 24) with a binomial (x – 3), the quotient is 6x + 14 and the remainder is 18.
Long Division of Polynomials by Other Polynomial
Long division of a polynomial with another polynomial is done when the expression is written in the standard form i.e. the terms of the dividend and the divisor are arranged in decreasing order of their degrees. The long division method for polynomials is considered the generalized version of the simple long division method done with numbers.
Let us look at an example to understand this better. The process of division is very similar to the rest of the methods.
Divide the polynomial 6x3 + 12x2 + 2x + 25 by x2 + 4x + 3. Here, 6x3 + 12x2 + 2x + 25 is the dividend, and x2 + 4x + 3 is the divisor which is also a polynomial.
- Step 1: Divide the first term of the dividend (6x3) by the first term of the divisor (x2), and put that as the first term in the quotient (6x).
- Step 2: Multiply the divisor by that answer, place the product (6x3 + 24x2 + 18x) below the dividend.
- Step 3: Subtract to create a new polynomial (-12x2 – 16x + 25).
- Step 4: Repeat the same process with the new polynomial obtained after subtraction.
So, when we are dividing a polynomial 6x3 + 12x2 + 2x + 25 with a binomial x2 + 4x + 3, the quotient is 6x – 12 and the remainder is 32x + 61.
What is Synthetic Division?
Synthetic division is a method used to perform the division operation on polynomials when the divisor is a linear factor. One of the advantages of using this method over the traditional long method is that the synthetic division allows one to calculate without writing variables while performing the polynomial division, which also makes it an easier method in comparison to the long division.
We can represent the division of two polynomials in the form:
p(x)/q(x) = Q(x) + R/(q(x))
where,
- p(x) is the dividend
- q(x) is the linear divisor
- Q(x) is quotient
- R is remainder
Synthetic Division Method
The following are the steps while performing synthetic division and finding the quotient and the remainder. We will take the following expression as a reference to understand it better: (2x3 – 3x2 + 4x + 5)/(x + 2)
- Check whether the polynomial is in the standard form.
- Write the coefficients in the dividend’s place and write the zero of the linear factor in the divisor’s place.
- Bring the first coefficient down.
- Multiply it with the divisor and write it below the next coefficient.
- Add them and write the value below.
- Repeat the previous 2 steps until you reach the last term.
- Separate the last term thus obtained which is the remainder.
- Now group the coefficients with the variables to get the quotient.
Therefore, the result obtained after synthetic division of (2x3 – 3x2 + 4x + 5)/(x + 2) is 2x2 – 7x + 18 and remainder is -31
How to do Synthetic Division?
Synthetic division of polynomials uses numbers for calculation and avoids the usage of variables. In the place of division, we multiply, and in the place of subtraction, we add.
- Write the coefficients of the dividend and use the zero of the linear factor in the divisor’s place.
- Bring the first coefficient down and multiply it with the divisor.
- Write the product below the 2nd coefficient and add the column.
- Repeat until the last coefficient. The last number is taken as the remainder.
- Take the coefficients and write the quotient.
- Note that the resultant polynomial is of one order less than the dividend polynomial.
Example:
1) Consider this division: (x3 – 2x3 – 8x – 35)/(x – 5). The polynomial is of order 3. The divisor is a linear factor. Let’s use synthetic division to find the quotient. Thus, the quotient is one order less than the given polynomial. It is x2 + 3x + 7 and the remainder is 0. (x3 – 2x3 – 8x – 35)/(x – 5) = x2 + 3x + 7.
Tips and Tricks on Synthetic Division:
- Write down the coefficients and divide them using the zero of the linear factor to obtain the quotient and the remainder. (P(x)/(x – a) = Q(x) + (R/(x – a))
- When we do synthetic division by (bx + a), we should get (Q(x)/b) as the quotient.
- Perform synthetic division only when the divisor is a linear factor.
- Perform multiplication and addition in the place of division and subtraction that is used in the long division method.